A car tank is 3/5 full. After using 6 liters, it is only 9/20 Full.how many liters does it hold when full.
Answer:
40 Liters
Step-by-step explanation:
To solve this problem, you can set up an equation. Let "x" represent the total number of liters the car's tank can hold when it's full.
Initially, the tank is 3/5 full, which can be represented as (3/5)x. After using 6 liters, it's 9/20 full, which can be represented as (3/5)x - 6 = (9/20)x.
Now, you can solve for x:
(3/5)x - 6 = (9/20)x
First, let's get rid of the fractions. You can do this by multiplying both sides of the equation by the least common multiple of 5 and 20, which is 20:
20 * ((3/5)x - 6) = 20 * ((9/20)x)
12x - 120 = 9x
Now, subtract 9x from both sides to isolate the x term:
12x - 9x - 120 = 0
3x - 120 = 0
Now, add 120 to both sides to solve for x:
3x = 120
Finally, divide by 3 to find the value of x:
x = 120 / 3
x = 40
So, the car's tank can hold 40 liters when it's full.